7x^(2/3)-55x^(1/3)-8=0

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Solution for 7x^(2/3)-55x^(1/3)-8=0 equation: 


x in (-oo:+oo)

7*x^(2/3)-(55*x^(1/3))-8 = 0

7*x^(2/3)-55*x^(1/3)-8 = 0

t_1 = x^(1/3)

7*t_1^2-55*t_1^1-8 = 0

7*t_1^2-55*t_1-8 = 0

DELTA = (-55)^2-(-8*4*7)

DELTA = 3249

DELTA > 0

t_1 = (3249^(1/2)+55)/(2*7) or t_1 = (55-3249^(1/2))/(2*7)

t_1 = 8 or t_1 = -1/7

t_1 = -1/7

x^(1/3)+1/7 = 0

1*x^(1/3) = -1/7 // : 1

x^(1/3) = -1/7

( -1/7 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 8

x^(1/3)-8 = 0

1*x^(1/3) = 8 // : 1

x^(1/3) = 8

x^(1/3) = 8 // ^ 3

x = 512

x = 512

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